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a) E1: N = 106, µ = 10-8, P = 10. E2: N = 105, µ = 10-8, P = 10.
b) E1: N = 107, µ = 10-8, P = 10. E2: N = 106, µ = 10-8, P = 10.
c) E1: N = 108, µ = 10-8, P = 10. E2: N = 107, µ = 10-8, P = 10.
d) E1: N = 109, µ = 10-8, P = 10. E2: N = 108, µ = 10-8, P = 10.
e) 10E1: N = 109, µ = 10-8, P = 10. 10E2: N = 108, µ = 10-8, P = 10.
f) 100E1: N = 109, µ = 10-8, P = 10. 100E2: N = 108, µ = 10-8, P = 10.
g) 200E1: N = 109, µ = 10-8, P = 10. 200E2: N = 108, µ = 10-8, P = 10.
h) E1: N = 108, µ = 10-8, P = 5. E2: N = 107, µ = 10-8, P = 5.
i) E1: N = 108, µ = 10-8, P = 50. E2: N = 107, µ = 10-8, P = 50.
 
Explain the obtained results. What hypothesis, adaptative or preadaptative, is better supported by the data?. What happens when increasing the number P of plates and/or the experiment replicates?. Please, note that the number appearing before the experiment identifier i.e. as in 10E1, refers to the number of experiment repetitions or replicates. That is, E1 stands for the results of performing the experiment-1 just one time while 10E1 refers to results averaged through 10 experiment replicates. Assuming that mutation ocurrence follows a Poisson distribution, estimate the mutation rate µ from the E2 experiment of case d) as 
µ = m / (Nt - N0).
 
Note that the expected number of mutations m that occurred per plate can be computed from the proportion p of cultures without mutants, being 
p = e-m